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Android Cannot Call Web Service

If phone, ensure that you have fast internet connection and further, you can increase the delay before you check for the result. more hot questions question feed default about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts Culture / Recreation My Code private static final String NAMESPACE = "http://tempuri.org/";//"http://localhost/TestWebService/" ; private static final String URL = "http://172.16.50.139/dbconnection/service.asmx";//"http://TestServer/Test/service.asmx"; private static final String HelloWorld_SOAP_ACTION = "http://tempuri.org/DBSelect";//"http://localhost/TestWebService/HelloWorld"; private static final String METHOD_NAME1 = "DBSelect"; Now i face different issue. his comment is here

For more information about creating a tracing rule for failed requests, click here. See the main.xml code as below: page

Word for "using technology inappropriately"? SoapObject request = new SoapObject(WSDL_TARGET_NAMESPACE,OPERATION_NAME); Now the operation or the method that you intend to call has some arguments which you need to attach to the request object. The request was received by the Web server, but during processing a fatal error occurred, causing the 500 error.

When the project is created, you will see that several files are added. Thanks! Thanks and Best Regards, E.Ravindran Sign In·ViewThread·Permalink Re: I am getting java.net.SocketTimedoutException Grasshopper.iics31-Mar-15 16:43 Grasshopper.iics31-Mar-15 16:43 Are you able to use your WebService from another client? Determine maximum frequency of input signal to make system LTI more hot questions question feed default about us tour help blog chat data legal privacy policy work here advertising info mobile

Regards, Sujeet KC 19-May-14 1:49am Hi prasad, I'm sorry, i checked the application running again and now its throwing SocketTimeoutException within 1 sec time period. It will also show the list of methods, which you cannot test. This is an important aspect of Android apps as it can easily be used to use existing business logic in Android rather than rewriting them. http://stackoverflow.com/questions/6805918/android-emulator-not-connecting-to-net-web-service Solution 1 Accept Solution Reject Solution Hello Sujeet, The localhost/127.0.0.1 in your code refers to the device on which the code is running, in this case the emulator.

General FAQ Ask a Question Bugs and Suggestions Article Help Forum Site Map Advertise with us About our Advertising Employment Opportunities About Us Articles » Web Development » Applications & Tools It is giving me an error when I typed the url in the browser of my emulator. Now I have Wcf Service method which returns a Person object which is created in .net. akbarjinna24-Sep-10 12:19 akbarjinna24-Sep-10 12:19 can u pl send me the full coding of this project sir,, Sign In·ViewThread·Permalink Re: Known issues with 3.6?

Sorry to bother... http://programmerguru.com/android-tutorial/how-to-call-java-web-service-in-android/ I have given like SOAP_ADDRESS = "http://192.168.8.0:15755/AddDemo.asmx"; where 192.168.8.0 is ip address of my system, 15755 is the port number and AddDemo.asmx is my web service. but not able to put on appropriate path Sign In·ViewThread·Permalink send image captured from camera sharan kumar14-Jun-11 0:18 sharan kumar14-Jun-11 0:18 Hi, I want to upload a image to web Things you can try: Ensure that the NTFS permissions for the web.config file are correct and allow access to the Web server's machine account.

Create a tracing rule to track failed requests for this HTTP status code. this content In this post, we are going to discuss about calling a web service from inside an Android application that has been developed using JEE technology. But I sure know where to put the WSDL file. KSOAP_ACTION, NAMESPACE, ... ) I know the METHOD and URL values, but don't know the others.

Please let me know if I am missing any step. So you need to host the service in a domain or real website. Check the event logs to see if any additional information was logged. weblink Rest/src/main/res/values/strings.xml Rest The ID is [id] The Content is [content] Refresh Create a layout The layout file is where you

PS: WebService is working fine. Add-in salt to injury? Sign In·ViewThread·Permalink having problem with paramenter passing kunal007719-Nov-13 20:21 kunal007719-Nov-13 20:21 i tried this tutorial it's very helpful.

IIS was not able to process configuration for the Web site or application.

Note the use of the string resources for the text of each widget. I can't thank you enough. Take a look at this post - http://programmerguru.com/android-tutorial/android-json-web-service-tutorial/ Edwin Thanks for tutorial! How did early mathematicians make it without Set theory?

But I can't define the parameters for ksoap package (i.e. SDK Add-on (each) 100 MB Optional. But at line:httpTransport.call(SOAP_ACTION, envelope);, it causes exception, it jumps to the catch exception. check over here Under Contents, select Create new project in workspace.

So how to know the arguments and return type? Is it unethical to poorly translate an exam from Dutch to English and then present it to the English speaking students? Modify the MainActivity to make a RESTful HTTP request and update the view. Sign In·ViewThread·Permalink Webservice not working omerfraz15-Nov-13 21:54 omerfraz15-Nov-13 21:54 For those of you need testing of this code for real webservice I am providing you the webService link please update

Sign In·ViewThread·Permalink http://grasshoppernetwork.com/member.php , registering a new user in grasshoppernetwork.com not working david2006es18-Nov-13 4:25 david2006es18-Nov-13 4:25 Hello, i'm trying to register a new user to http://grasshoppernetwork.com[^] It shows an exception: Sign In·ViewThread·Permalink Where to add ServiceImpl.wsdl in android app, help! Error is occuring http://programmerguru.com/android-tutorial/ Android Guru @disqus_PEBx4m7FRz:disqus, Can you post error message here so that I can help you? Donate Donate us as little as Rs.10(Indian Rupees) to continue to serve you.

For this mobile application, the following line has to be added: Android, web services This entry was posted on Thursday, March 3, 2011 and is filed under Android.